Hello friends, in this article, we are going to learn a superposition theorem. We will also solve some simple examples using superposition theorem.

## Statement of Superposition Theorem

Superposition theorem states that the response in any element of LTI linear bilateral network containing more than one sources is the sum of the responses produced by the sources each acting independently.

The superposition theorem is not applicable for the power, as power is directly proportional to the square of the current which is not a linear function.

## Steps

- Select any one source and short all other voltage sources and open all current sources if the internal impedance is not known. If known replace them by their impedance.
- Find out the current or voltage across the required element, due to the source under consideration.
- Repeat the above steps for all other sources.
- Add all the individual effects produced by individual sources to obtain the total current in or across the voltage element.

## Example

Using the superposition theorem, determine the voltage drop and current across the resistor 3.3K as shown in the figure below.

## Solution

**Step 1: **Remove the 8V power supply from the original circuit, such that the new circuit becomes as the following and then measure the voltage across a resistor.

Here 3.3K and 2K are in parallel, therefore resultant resistance will be 1.245K.

Using voltage divider rule voltage across 1.245K will be

V1= [1.245/(1.245+4.7)]*5 = 1.047V

**Step 2:** Remove the 5V power supply from the original circuit such that the new circuit becomes as the following and then measure the voltage across a resistor.

Here 3.3K and 4.7K are in parallel, therefore resultant resistance will be 1.938K.

Using voltage divider rule voltage across 1.938K will be

V2= [1.938/(1.938+2)]*8 = 3.9377V

Therefore voltage drop across a 3.3K resistor is V1+V2 = 1.047+3.9377=4.9847

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Tags: superposition theorem solved problems, superposition theorem examples, superposition principle.